The file-*-save procedure do not save the image, they save a layer. What happened in your case is likely that the initial layer is no more. If you merged things (gimp_image_flatten(), gimp_image_merge_down() and a few others) the result is a new layer, but the call returns the layer created. So you just have to keep that returned value.

If your image still has several layers at the end, instead of flattening you can also use gimp_layer_new_from_visible() and save the returned layer.

to get the layer again that you merged. Are you using GIMP's PPB or PDB? The procedure Browser is your best friend!

I have the new_layer returned by several procedures I tried. That's not the problem.

What do I do with it? pdb.file_jpeg_save doesn't accept layer as a parameter.

Thank you for the response.

I guessed that much. In fact, after the post, I did a pdb.gimp_image_merge_down to get a new layer but pdb.file_jpeg_save doesn't take layers as a parameter.

pdb.file_jpeg_save(image, drawable, filename, raw_filename, quality, smoothing, optimize, progressive, comment, subsmp, baseline, restart, dct)

I tried

pdb.gimp_image_set_active_layer(image, newLayer)

and that doesn't do anything.


So what do I do with the returned layer?

Of course it does. A layer is a drawable (a drawable is a layer, a channel or a mask), so the "drawable" parameter should be the layer returned by pdb.gimp_image_merge_down().

I am very comfortable with Python.

Then you should have found this:

>>> layer=gimp.image_list()[0].active_layer
>>> layer.__class__.__mro__
(<type 'gimp.Layer'>, <type 'gimp.Drawable'>, <type 'gimp.Item'>, <type 'object'>)

Alright. You got me stumped. I know syntactically what these statements are but how would they have helped me realize "Drawable" means I can pass the "layer" to it?

For me as a newbie, I thought it's a typo for "Drawtable"!!!